(x+1)(x-1)(x-2)(x^2+7x)(x-4)-2-2x=0

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Solution for (x+1)(x-1)(x-2)(x^2+7x)(x-4)-2-2x=0 equation: 



(x+1)(x-1)(x-2)(x^2+7x)(x-4)-2-2x=0

We add all the numbers together, and all the variables

-2x+(x+1)(x-1)(x-2)(x^2+7x)(x-4)-2=0

We multiply parentheses ..

(+x^2-1x+x-1)(x-2)(x^2+7x)(x-4)-2x-2=0

We move all terms containing x to the left, all other terms to the right

(+x^2-1x+x-1)(x-2)(x^2+7x)(x-4)-2x=2

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